Question #198768

Define: R^3→R^3 by


T(x,y,z)=(x-y+z,x+y,y+z)


Let v1= (1,1,1), v2= (0,1,1), v3= (0,0,1). Find a matrix of T with respect to the basis {v1,v2,v3}. Futher check T is invertible or not.


1
Expert's answer
2021-06-02T13:55:57-0400

V1=[1,1,1]V_1=[1,1,1]

V2=[0,1,1]V_2=[0,1,1]

V3=[0,0,1]V_3=[0,0,1]


T=[xy+z,x+y,y+z]T=[x-y+z,x+y,y+z]


According to this the new


V1=[1,2,2]V_1'=[1,2,2]

V2=[0,1,2]V_2'=[0,1,2]

V3=[1,0,1]V_3'=[1,0,1]


So the matrix T form is as follows:


T=T= [122012101]\begin{bmatrix} 1 & 2 & 2 \\ 0 & 1 & 2\\ 1 & 0 & 1 \end{bmatrix}


For the invertible matrix the determinant of the matrix is = 0


Det(T) = 1(10)2(02)+2(01)=1+42=31(1-0)-2(0-2)+2(0-1)=1+4-2=3


As the determinant of the matrix is not equal to zero hence the given matrix is invertible.



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