Let x = no of tanks of crude oil and y = no of tanks of petrol.
We are to maximise 5000x+3000y subject to conditions:
2x+y=10−(1)
x+y=8−(2)
Using substitution method
x=2 and y=6
Substituting x and y in 5000x + 3000y, we have that the maximum profit he can make
is 28000 Ghana cedis
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Very great works out there