solve the system of linear equations.
x-y + 2z = 5
2x - 2y + 4z = 10
3x - 3y + 6z = 15
"x-y+2z=5\\\\\n2x-2y+4z=10\\\\\n3x-3y+6z=15""\\Darr""x-y+2z=5\\\\\n2x-2y+4z=10\\space|\\space\/2\\\\\n3x-3y+6z=15\\space|\\space\/3""\\Darr""x-y+2z=5\\\\\nx-y+2z=5\\\\\nx-y+2z=5""\\Darr""x-y+2z=5"
Answer: ("y-2z+5"; "y"; "z") where "y\\space\\epsilon\\space\u211d", "z\\space\\epsilon\\space\u211d".
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