Let v=c1a1+c2a2+c3a3⇒⎣⎡pqr⎦⎤T=c1×⎣⎡10−1⎦⎤T+c2×⎣⎡111⎦⎤T+c3×⎣⎡100⎦⎤T⇒⎣⎡pqr⎦⎤T=⎣⎡c1c2c3⎦⎤T×⎣⎡10−1111100⎦⎤T⇒⎣⎡pqr⎦⎤=⎣⎡10−1111100⎦⎤×⎣⎡c1c2c3⎦⎤By Row-reducing we get,⇒⎣⎡q−rqp+r−2q⎦⎤=⎣⎡100010001⎦⎤×⎣⎡c1c2c3⎦⎤⇒c1=q−r,c2=q,c3=p+r−2q
So, v = (p,q,r) as a linear combination of the basis vectors from B :-
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