The standard basis for R2 is (1,0) and (0,1)
T(1,0)=(0,1)
T(0,1)= (-1,0)
Thematrix of the given linear transformation is given by
A= "\\begin{bmatrix}\n 0 & -1 \\\\\n 1 & 0\n\\end{bmatrix}"
The characteristic polynomial is given by
"Det(A-xI) = \\begin{vmatrix}\n -x& -1\\\\\n 1& -x\n\\end{vmatrix}" =0
"x^2 +1 =0\\\\"
But if F=R, then the characteristic polynomial has no zeroes in R.
So, there are no eigenvalues and no eigenvectors when F=R.
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