f(x1,x2)=3x1+4x2T(x1,x2)=(x1−x2,x1+x2)g(x1,x2)=f(x1,x2)∘T(x1,x2)==3(x1−x2)+4(x1+x2)=7x1+x2g(2,3)=7⋅2+3=17f(x_1,x_2)=3x_1+4x_2\\ T(x_1,x_2)=(x_1-x_2,x_1+x_2)\\ g(x_1,x_2)=f(x_1,x_2)\circ T(x_1,x_2)=\\ =3(x_1-x_2)+4(x_1+x_2)=7x_1+x_2\\ g(2,3)=7\cdot2+3=17f(x1,x2)=3x1+4x2T(x1,x2)=(x1−x2,x1+x2)g(x1,x2)=f(x1,x2)∘T(x1,x2)==3(x1−x2)+4(x1+x2)=7x1+x2g(2,3)=7⋅2+3=17
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