Given that M = 2 −1
−3 4
and that M^2 − 6M + kI = 0, find k.
1
2020-05-28T18:01:34-0400
M=(2−3−14)
M2=(2−3−14)(2−3−14)=
=(2(2)−1(−3)−3(2)+4(−3)2(−1)−1(4)−3(−1)+4(4))=
=(7−18−619)
M2−6M=(7−18−619)−(12−18−624)=
=(−500−5)=−5(1001)=−5I k=5
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