Given that , A−1=B .
1) We known that,
adj(PQ)=(adjQ)(adjP),for any square matrix P,Q of the same order.
And adj(I)=I ,where I is the identity matrix.
Since AB=I=BA
Therefore, adj(AB)=adj(I)=adj(BA).
⟹(adjB)(adjA)=I=(adjA)(adjB)
⟹(adjB)=(adjA)−1 .
2) We known that (PQ)T=QTPT for any square matrix P,Q of same order .
Since ,AB=I=BA
⟹(AB)T=IT=(BA)T
⟹BTAT=I=ATBT, as IT=I
⟹BT=(AT).−1
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