Answer to Question #102058 in Linear Algebra for Alam Sha

Question #102058
Suppose that A is a 3x3 matrix and that b is a 3x1 matrix. Assuming that
the matrix equation Ax = b has infinitely many solutions, write down all the possible
reduced row-echelon forms of the augmented matrix (A | b). You may use ‘*’ to
represent an unknown number.
1
Expert's answer
2020-01-30T13:01:33-0500

Consider the matrix

A=(a11a12a13a21a22a23a31a32a33)A=\begin{pmatrix} a_{11} &a_{12}&a_{13} \\ a_{21} &a_{22}&a_{23} \\ a_{31} &a_{32}&a_{33} \\ \end{pmatrix}

X=(x1x2x3)X=\begin{pmatrix} x_1 \\ x_2\\ x_3 \end{pmatrix}

b=(b1b2b3)b=\begin{pmatrix} b_1 \\ b_2\\ b_3 \end{pmatrix}

Subject to the problem the matrix equation

Ax=bAx = b

has infinitely many solutions then detA=0,rank(A)<3det A=0, rank(A)<3.

The matrix equation Ax=bAx = b :


{a11x1+a12x2+a13x3=b1a21x1+a22x2+a23x3=b2a31x1+a32x2+a33x3=b3\left\{\begin{matrix} a_{11}x_1+ a_{12}x_2+a_{13}x_3=b_1\\ a_{21}x_1+ a_{22}x_2+a_{23}x_3=b_2\\ a_{31}x_1+ a_{32}x_2+a_{33}x_3=b_3\\ \end{matrix}\right.

Consider the matrix

(Ab)=(a11a12a13b1a21a22a23b2a31a32a33b3)(A|b)=\begin{pmatrix} a_{11} &a_{12}&a_{13} &|b_1\\ a_{21} &a_{22}&a_{23} &|b_2\\ a_{31} &a_{32}&a_{33} &|b_3\\ \end{pmatrix}

Suppose a110,rank(A)=2a_{11}\neq 0, rank(A)=2


(Ab)(1a12a11a13a11b1a11a21a22a23b2a31a32a33b3)R2+R1(a21)R3+R1(a31)(10c22c23c20c32c33c3)(A|b) \leftrightarrow\begin{pmatrix} 1 &\frac{a_{12}}{a_{11}}&\frac{a_{13}}{a_{11}} &|\frac{b_1}{a_{11}}\\ a_{21} &a_{22}&a_{23} &|b_2\\ a_{31} &a_{32}&a_{33} &|b_3\\ \end{pmatrix} \leftrightarrow\\ \begin{matrix} R_2+R_1(-a_{21}) \\ R_3+R_1(-a_{31}) \end{matrix}\\ \leftrightarrow \begin{pmatrix} 1 &*&* &|*\\ 0 &c_{22}&c_{23} &|c_2\\ 0 &c_{32}&c_{33} &|c_3\\ \end{pmatrix}

c220,rg(A)=2c_{22}\neq 0, rg(A)=2

perform operations over rows

R2c22R3+R2(c32)\frac{R_2}{c_{22}}\\ R_3+R_2(-c_{32})


(Ab)(1010000)(A|b)\leftrightarrow \begin{pmatrix} 1 &*&* &|*\\ 0 &1&* &|*\\ 0 &0&0 &|0\\ \end{pmatrix}

Similarly, if rank(A)=1,a110rank(A)=1, a_{11}\neq 0, then

(Ab)(100000000)(A|b)\leftrightarrow \begin{pmatrix} 1 &*&* &|*\\ 0 &0&0 &|0\\ 0 &0&0 &|0\\ \end{pmatrix}


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