Consider the matrix
A = ( a 11 a 12 a 13 a 21 a 22 a 23 a 31 a 32 a 33 ) A=\begin{pmatrix}
a_{11} &a_{12}&a_{13} \\
a_{21} &a_{22}&a_{23} \\
a_{31} &a_{32}&a_{33} \\
\end{pmatrix} A = ⎝ ⎛ a 11 a 21 a 31 a 12 a 22 a 32 a 13 a 23 a 33 ⎠ ⎞
X = ( x 1 x 2 x 3 ) X=\begin{pmatrix}
x_1 \\
x_2\\
x_3
\end{pmatrix} X = ⎝ ⎛ x 1 x 2 x 3 ⎠ ⎞
b = ( b 1 b 2 b 3 ) b=\begin{pmatrix}
b_1 \\
b_2\\
b_3
\end{pmatrix} b = ⎝ ⎛ b 1 b 2 b 3 ⎠ ⎞
Subject to the problem the matrix equation
A x = b Ax = b A x = b
has infinitely many solutions then d e t A = 0 , r a n k ( A ) < 3 det A=0, rank(A)<3 d e t A = 0 , r ank ( A ) < 3 .
The matrix equation A x = b Ax = b A x = b :
{ a 11 x 1 + a 12 x 2 + a 13 x 3 = b 1 a 21 x 1 + a 22 x 2 + a 23 x 3 = b 2 a 31 x 1 + a 32 x 2 + a 33 x 3 = b 3 \left\{\begin{matrix}
a_{11}x_1+ a_{12}x_2+a_{13}x_3=b_1\\
a_{21}x_1+ a_{22}x_2+a_{23}x_3=b_2\\
a_{31}x_1+ a_{32}x_2+a_{33}x_3=b_3\\
\end{matrix}\right. ⎩ ⎨ ⎧ a 11 x 1 + a 12 x 2 + a 13 x 3 = b 1 a 21 x 1 + a 22 x 2 + a 23 x 3 = b 2 a 31 x 1 + a 32 x 2 + a 33 x 3 = b 3
Consider the matrix
( A ∣ b ) = ( a 11 a 12 a 13 ∣ b 1 a 21 a 22 a 23 ∣ b 2 a 31 a 32 a 33 ∣ b 3 ) (A|b)=\begin{pmatrix}
a_{11} &a_{12}&a_{13} &|b_1\\
a_{21} &a_{22}&a_{23} &|b_2\\
a_{31} &a_{32}&a_{33} &|b_3\\
\end{pmatrix} ( A ∣ b ) = ⎝ ⎛ a 11 a 21 a 31 a 12 a 22 a 32 a 13 a 23 a 33 ∣ b 1 ∣ b 2 ∣ b 3 ⎠ ⎞
Suppose a 11 ≠ 0 , r a n k ( A ) = 2 a_{11}\neq 0, rank(A)=2 a 11 = 0 , r ank ( A ) = 2
( A ∣ b ) ↔ ( 1 a 12 a 11 a 13 a 11 ∣ b 1 a 11 a 21 a 22 a 23 ∣ b 2 a 31 a 32 a 33 ∣ b 3 ) ↔ R 2 + R 1 ( − a 21 ) R 3 + R 1 ( − a 31 ) ↔ ( 1 ∗ ∗ ∣ ∗ 0 c 22 c 23 ∣ c 2 0 c 32 c 33 ∣ c 3 ) (A|b) \leftrightarrow\begin{pmatrix}
1 &\frac{a_{12}}{a_{11}}&\frac{a_{13}}{a_{11}} &|\frac{b_1}{a_{11}}\\
a_{21} &a_{22}&a_{23} &|b_2\\
a_{31} &a_{32}&a_{33} &|b_3\\
\end{pmatrix} \leftrightarrow\\
\begin{matrix}
R_2+R_1(-a_{21}) \\
R_3+R_1(-a_{31})
\end{matrix}\\
\leftrightarrow
\begin{pmatrix}
1 &*&* &|*\\
0 &c_{22}&c_{23} &|c_2\\
0 &c_{32}&c_{33} &|c_3\\
\end{pmatrix} ( A ∣ b ) ↔ ⎝ ⎛ 1 a 21 a 31 a 11 a 12 a 22 a 32 a 11 a 13 a 23 a 33 ∣ a 11 b 1 ∣ b 2 ∣ b 3 ⎠ ⎞ ↔ R 2 + R 1 ( − a 21 ) R 3 + R 1 ( − a 31 ) ↔ ⎝ ⎛ 1 0 0 ∗ c 22 c 32 ∗ c 23 c 33 ∣ ∗ ∣ c 2 ∣ c 3 ⎠ ⎞
c 22 ≠ 0 , r g ( A ) = 2 c_{22}\neq 0, rg(A)=2 c 22 = 0 , r g ( A ) = 2
perform operations over rows
R 2 c 22 R 3 + R 2 ( − c 32 ) \frac{R_2}{c_{22}}\\
R_3+R_2(-c_{32}) c 22 R 2 R 3 + R 2 ( − c 32 )
( A ∣ b ) ↔ ( 1 ∗ ∗ ∣ ∗ 0 1 ∗ ∣ ∗ 0 0 0 ∣ 0 ) (A|b)\leftrightarrow \begin{pmatrix}
1 &*&* &|*\\
0 &1&* &|*\\
0 &0&0 &|0\\
\end{pmatrix} ( A ∣ b ) ↔ ⎝ ⎛ 1 0 0 ∗ 1 0 ∗ ∗ 0 ∣ ∗ ∣ ∗ ∣0 ⎠ ⎞
Similarly, if r a n k ( A ) = 1 , a 11 ≠ 0 rank(A)=1, a_{11}\neq 0 r ank ( A ) = 1 , a 11 = 0 , then
( A ∣ b ) ↔ ( 1 ∗ ∗ ∣ ∗ 0 0 0 ∣ 0 0 0 0 ∣ 0 ) (A|b)\leftrightarrow \begin{pmatrix}
1 &*&* &|*\\
0 &0&0 &|0\\
0 &0&0 &|0\\
\end{pmatrix} ( A ∣ b ) ↔ ⎝ ⎛ 1 0 0 ∗ 0 0 ∗ 0 0 ∣ ∗ ∣0 ∣0 ⎠ ⎞
Comments
Leave a comment