Question #102058

Suppose that A is a 3x3 matrix and that b is a 3x1 matrix. Assuming that

the matrix equation Ax = b has infinitely many solutions, write down all the possible

reduced row-echelon forms of the augmented matrix (A | b). You may use ‘*’ to

represent an unknown number.

Expert's answer

Consider the matrix

A=(a11a12a13a21a22a23a31a32a33)A=\begin{pmatrix} a_{11} &a_{12}&a_{13} \\ a_{21} &a_{22}&a_{23} \\ a_{31} &a_{32}&a_{33} \\ \end{pmatrix}

X=(x1x2x3)X=\begin{pmatrix} x_1 \\ x_2\\ x_3 \end{pmatrix}

b=(b1b2b3)b=\begin{pmatrix} b_1 \\ b_2\\ b_3 \end{pmatrix}

Subject to the problem the matrix equation

Ax=bAx = b

has infinitely many solutions then detA=0,rank(A)<3det A=0, rank(A)<3.

The matrix equation Ax=bAx = b :


{a11x1+a12x2+a13x3=b1a21x1+a22x2+a23x3=b2a31x1+a32x2+a33x3=b3\left\{\begin{matrix} a_{11}x_1+ a_{12}x_2+a_{13}x_3=b_1\\ a_{21}x_1+ a_{22}x_2+a_{23}x_3=b_2\\ a_{31}x_1+ a_{32}x_2+a_{33}x_3=b_3\\ \end{matrix}\right.

Consider the matrix

(A∣b)=(a11a12a13∣b1a21a22a23∣b2a31a32a33∣b3)(A|b)=\begin{pmatrix} a_{11} &a_{12}&a_{13} &|b_1\\ a_{21} &a_{22}&a_{23} &|b_2\\ a_{31} &a_{32}&a_{33} &|b_3\\ \end{pmatrix}

Suppose a11≠0,rank(A)=2a_{11}\neq 0, rank(A)=2


(A∣b)↔(1a12a11a13a11∣b1a11a21a22a23∣b2a31a32a33∣b3)↔R2+R1(−a21)R3+R1(−a31)↔(1∗∗∣∗0c22c23∣c20c32c33∣c3)(A|b) \leftrightarrow\begin{pmatrix} 1 &\frac{a_{12}}{a_{11}}&\frac{a_{13}}{a_{11}} &|\frac{b_1}{a_{11}}\\ a_{21} &a_{22}&a_{23} &|b_2\\ a_{31} &a_{32}&a_{33} &|b_3\\ \end{pmatrix} \leftrightarrow\\ \begin{matrix} R_2+R_1(-a_{21}) \\ R_3+R_1(-a_{31}) \end{matrix}\\ \leftrightarrow \begin{pmatrix} 1 &*&* &|*\\ 0 &c_{22}&c_{23} &|c_2\\ 0 &c_{32}&c_{33} &|c_3\\ \end{pmatrix}

c22≠0,rg(A)=2c_{22}\neq 0, rg(A)=2

perform operations over rows

R2c22R3+R2(−c32)\frac{R_2}{c_{22}}\\ R_3+R_2(-c_{32})


(A∣b)↔(1∗∗∣∗01∗∣∗000∣0)(A|b)\leftrightarrow \begin{pmatrix} 1 &*&* &|*\\ 0 &1&* &|*\\ 0 &0&0 &|0\\ \end{pmatrix}

Similarly, if rank(A)=1,a11≠0rank(A)=1, a_{11}\neq 0, then

(A∣b)↔(1∗∗∣∗000∣0000∣0)(A|b)\leftrightarrow \begin{pmatrix} 1 &*&* &|*\\ 0 &0&0 &|0\\ 0 &0&0 &|0\\ \end{pmatrix}


LATEST TUTORIALS
APPROVED BY CLIENTS