Question

A floor which measures 15 m*8 m is to be laid with tiles measuring 50 cm*25 cm. Find the number of tiles required. Further, if a carpet is laid on the floor so that a space of 1 m exists between its edges of the floor, what fraction of the floor is uncovered?

Answer 1

Answer on Question #43988, Math, Geometry

A floor which measures 15 m*8 m is to be laid with tiles measuring 50 cm*25 cm. Find the number of tiles required. Further, if a carpet is laid on the floor so that a space of 1 m exists between its edges of the floor, what fraction of the floor is uncovered?

Solution

You will need

$N=$ (tiles you need on 8 m side) $\times$ (tiles you need on 15 m side) $=$

$=8/0.25\times 15/0.5=32\times 30=960\,tiles$

Fraction of uncovered when there is 1 m gap is

$k=\frac{\text{area of gap}}{\text{total area}}=\frac{2(8+15)\cdot 1}{8\cdot 15}\approx 0.38$

Area of gap was found as perimeter multiplied by width = 1 m.

www.AssignmentExpert.com