Question

A cistern 6 m long, 4 m wide, contains water to a depth of 1 m 25 cm : find the area of the wet surface.

Answer 1

Answer on Question #43984 – Math – Geometry

A cistern 6 m long, 4 m wide, contains water to a depth of 1 m 25 cm : find the area of the wet surface.

Solution.

The area of the bottom wet face of a cistern is equal to

$$S _ {1} = 6 \cdot 4 = 2 4 \mathrm {m} ^ {2}.$$

The area of the front and back wet faces of a cistern is equal to

$$S _ {2} = 6 \cdot 1. 2 5 = 7. 5 \mathrm {m} ^ {2}.$$

The area of the left and right wet faces of a cistern is equal to

$$S _ {3} = 4 \cdot 1. 2 5 = 5 \mathrm {m} ^ {2}.$$

The area of the wet surface is equal to

$$S = S _ {1} + 2 S _ {2} + 2 S _ {3} = 2 4 + 1 5 + 1 0 = 4 9 \mathrm {m} ^ {2}.$$

Answer. $S = 49 \mathrm{~m}^{2}$ .

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