A right circular cone is inscribed in a cube having an edge which measures 20 cm. Find the lateral area and volume of the cone
Solution
For cone inscribed in a cube with edge a=20 cm its diameter d=a and height h=a.
So volume V = (1/3)*AB*h = (1/3)*(π*d2/4)*h = π*d2*h/12 = π*a3/12 = π*203/12 = π*2000/3 ≈ 2094.4 cm3 (AB is area of the cone base).
The slant height of a right circular cone "L=\\sqrt{(d\/2)^2+h^2}=a\\sqrt{5}\/2"
Lateral area "LSA=\\pi d L\/2= \\pi a^2 \\sqrt{5}\/4 \\approx 702.48 cm^2"
Answer
volume V = π*a3/12 ≈ 2094.4 cm3
lateral area "LSA= \\pi a^2 \\sqrt{5}\/4 \\approx 702.48 cm^2"
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