Answer to Question #153643 in Geometry for Janine Leodones

Question

A garden plot is to contain 128 sq. ft. If its length is to be twice its width, what should its dimensions be?

Answer 1

It is given that garden plot is to contain $128$ sq.ft .

Therefore area of the garden plot is $128$ sq.ft.

According to the problem length of the garden plot is twice its width.

Let width of the garden plot is $l$ ft.

Then length of the garden plot will be $2l$ ft.

Therefore area of the garden plot is

$= 2l×l$ sq.ft.

$=2l^2$ sq.ft.

According to the problem,

$2l^2=128$

$\implies l^2=64$

$\implies l=\sqrt{64}$

$\implies l=8$

So width of the garden plot is $= 8$ ft.

Therefore length of the garden plot is $=16$ ft.

Therefore dimensions of the garden plot is $16$ ft. by $8$ ft.