Given a cube with a volume of 27 cm3, what is the volume of a square pyramid that can fit perfectly inside the cube?
3cm3
6cm3
9cm3
12cm3
Let us determine the edge "a" of the cube. The volume is "V=a^3=27," therefore "a = \\sqrt[3]{27} = 3\\,\\mathrm{cm}."
The square pyramid has the square base of area "S=a^2 = 9\\,\\mathrm{cm}^2" and the height of "a" . The volume of a pyramid is "V_p = \\dfrac13\\cdot S\\cdot h = \\dfrac13\\cdot 9\\,\\mathrm{cm}^2\\cdot 3\\,\\mathrm{cm} = 9\\,\\mathrm{cm}^3."
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