Question #139801
In a Banach space, show that every absolutely convergent series is convergent.
1
Expert's answer
2020-10-25T18:36:04-0400

Let XX be Banach space.

Let k=1ak\sum\limits_{k=1}^{\infty}a_k be an absolutely convergent series in XX , that is k=1ak\sum\limits_{k=1}^{\infty}\|a_k\| is a convergent series.

Denote k=1nak\sum\limits_{k=1}^na_k by SnS_n, and let S0=0S_0=0.

By the Cauchy's convergence test we have that for every ε>0\varepsilon>0 there is NNN\in\mathbb N such that k=nmak<ε\sum\limits_{k=n}^m\|a_k\|<\varepsilon for every n,m>N,mnn,m>N, m\ge n.

By the general triangle inequality we have SmSn1=k=nmakk=nmak\|S_m-S_{n-1}\|=\bigl\|\sum\limits_{k=n}^ma_k\bigr\|\le\sum\limits_{k=n}^m\|a_k\|, so {Sn}nN\{S_n\}_{n\in\mathbb N} is a fundamental sequence in XX. Since XX is Banach space, we have that {Sn}nN\{S_n\}_{n\in\mathbb N} is a convergent sequence, that is k=1ak\sum\limits_{k=1}^{\infty}a_k is a convergent series.


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