Suppose that f is a sub additive functional on X. Then, by definition, we have
∀x,y∈Xf(x+y)≤f(x)+f(y). For any x∈X outside a sphere f(x)≥0 . Suppose that x~ lies either inside a sphere or on its boundary. This means that ∣∣x~∣∣=α≤r. We consider two cases:
- α>0 . We set n=[αr]+2 , where [] denotes the truncation. Then nα>r . It means, that ∣∣nx~∣∣>r and nx~ lies outside the sphere. Using sub additivity, we get 0≤f(nx~)=f((n−1)x~+x~)≤f(x~)+f((n−2)x~+x~)≤...≤nf(x~)
Therefore, we have f(x~)≥0 .
2. α=0 . Using the definition of the norm, we have x~=0 . Assume that x∈X is outside the sphere. Then, f(x+0)≤f(0)+f(x). From the latter we get f(0)≥0 .
Thus, f(x)≥0 for all x∈X.
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