EXPLANATION.
Denote by (X,∥∥) the normalized space. f(x)=∥x∥, f:X→R1
By the properties of the norm for any x,a∈X the inequalities∥x∥=∣∣x−a+a∣∣≤∥x−a∥+∥a∥ , ∥a∥=∣∣a−x+x∣∣≤∥x−a∥+∥x∥ are true. Hence, −(∥x∥−∥a∥)≤∥x−a∥≤(∥x∥−∥a∥) , or
∣∥x∥−∥a∥∣≤∥x−a∥. For the function f the last inequality means
∣f(x)−f(a)∣≤∥x−a∥ (1)
Let ε>0,δ=ε . Then from inequality (1) we obtain ,that for all x,a∈X
∥x−a∥<δ implies ∣f(x)−f(a)∣≤∥x−a∥<δ=ε (2)
By the definition of continuous function ,(2) means, that f is continuous at any point a∈X .
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