solution
The interest rate, "4\\%" p.a hence the monthly compounding rate (r) is:
The savings:
"Payment,p=250"
"Number \\ of \\ payments,n=12"
The value of the payments at the end of 1 year
"=250*\\frac{ (1+ \\frac{0.04}{12} )^{12}-1}{\\frac{0.04}{12}}=3055.6157"
Withdrawal:
At the end of the savings period, The present value of withdrawal amounts should be equal to the accumulated value of savings:
"PV=p*\\frac{ 1-(1+r)^{-n}}{r}"
"3055.6157=p*\\frac{ 1-(1+ \\frac{0.04}{12})^{-6}}{ \\frac{0.04}{12}}""3055.6157= p* 5.9306"
"p=\\frac{3055.6157}{5.9306} =515.2272"
answer: the bank pays $515.23 at the end of every month for 6 months
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