2020-09-24T23:44:25-04:00
The present value of a series of payments of $3 at the end of every eight years, forever, is
equal to $9.5. Calculate the effective annual rate of interest.
1
2020-10-04T17:54:15-0400
ν = 1 1 + i \nu=\dfrac{1}{1+i} ν = 1 + i 1
P V = 3 ⋅ ν 8 + 3 ⋅ ν 16 + . . . = 3 ⋅ ν 8 1 − ν 8 = 9.5 PV=3\cdot\nu^8 +3\cdot\nu^{16}+...=\dfrac{3\cdot \nu^8}{1-\nu^8 }=9.5 P V = 3 ⋅ ν 8 + 3 ⋅ ν 16 + ... = 1 − ν 8 3 ⋅ ν 8 = 9.5
ν 8 = 9.5 12.5 = 0.76 \nu^8=\dfrac{9.5}{12.5}=0.76 ν 8 = 12.5 9.5 = 0.76
1 1 + i = 0.76 8 \dfrac{1}{1+i}=\sqrt[8]{0.76} 1 + i 1 = 8 0.76
i = 1 0.76 8 − 1 ≈ 0.0349 i=\dfrac{1}{\sqrt[8]{0.76}}-1\approx0.0349 i = 8 0.76 1 − 1 ≈ 0.0349
i = 3.49 % i=3.49\% i = 3.49%
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