Question #135119

A borrower agrees to repay a loan of $3000 by 15 annual repayments of $500, the first repayment being due after five years. Find the annual yield for this transaction.

Expert's answer

Assume that the annual rate is ii. Then we have:

500(1(1+i)5+1(1+i)6+..+1(1+i)20)=3000500(\frac{1}{(1+i)^5}+\frac{1}{(1+i)^6}+..+\frac{1}{(1+i)^{20}})=3000 .

After simplifications we get:

500(1+i)5(11(1+i)16)11(1+i)=3000\frac{500}{(1+i)^5}\frac{(1-\frac{1}{(1+i)^{16}})}{1-\frac{1}{(1+i)}}=3000

From it we receive:

(1(1+i)51(1+i)21)=6(11(1+i)){(\frac{1}{(1+i)^5}-\frac{1}{(1+i)^{21}})}=6(1-\frac{1}{(1+i)})

Solving the latter numerically, we obtain:

1(1+i)=0.91903\frac{1}{(1+i)}=0.91903

From the latter we obtain i:

i0.0881.i\approx0.0881.

Answer: 0.0881(the values is rounded to 4 decimal places)


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