Question #307160

How many 10-bit strings contain 6 or more 1’s? Explain and show all the steps.

1
Expert's answer
2022-03-07T22:13:03-0500

Number of strings with 6 1's: C106=10!6!4!=210.C_{10}^6=\frac{10!}{6!4!}=210.

Number of strings with 7 1's: C107=10!7!3!=120.C_{10}^7=\frac{10!}{7!3!}=120.

Number of strings with 8 1's: C108=10!8!2!=45.C_{10}^8=\frac{10!}{8!2!}=45.

Number of strings with 9 1's: C106=10!9!1!=10.C_{10}^6=\frac{10!}{9!1!}=10.

Number of strings with 10 1's: C1010=10!10!0!=1.C_{10}^{10}=\frac{10!}{10!0!}=1.

Number of strings with 6 or more 1's: N=210+120+45+10+1=386.N=210+120+45+10+1=386.

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