Question #276287

Let f : A → B be a function.


1. Show that for the identity function iA on A we have f ◦ iA = f.


2. Show that for the identity function iB on B we have iB ◦ f = f.





1
Expert's answer
2021-12-07T11:42:04-0500

f: ABf:\ A\rightarrow B

1. aA:(fIA)(a)=f(IA(a))\forall a \in A:\quad (f\circ I_A)(a)=f\big(I_A(a)\big)

Since aAa\in A , it follows that IA(a)=aI_A(a)=a and (fIA)(a)=f(IA(a))=f(a)(f\circ I_A)(a)=f\big(I_A(a)\big)=f(a)

So, fIA=ff\circ I_A=f .


2. aA:(IBf)(a)=IB(f(a))\forall a \in A:\quad (I_B\circ f)(a)=I_B\big(f(a)\big)

Since f(a)Bf(a)\in B , it follows that IB(f(a))=f(a)I_B\big(f(a)\big)=f(a) and (IBf)(a)=f(a)(I_B\circ f)(a)=f(a)

So, IBf=fI_B\circ f=f .


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