Answer to Question #275661 in Discrete Mathematics for Zahir

Question

∑ (2 𝑗+1 − 2 𝑗 ) 8 𝑗=0 

Answer 1

$\displaystyle\sum_{j=0}^8(2 𝑗+1 − 2 𝑗 )=\displaystyle\sum_{j=0}^81=9$