Consider the following relation R on A where A = {1, 2, 3, 4, 5}
aRb ⇔
a
b
< min(a, b)
For example, 2R4 since
2
4
=
1
2
and min(2, 4) = 2 and 1
2
< 2.
(a) Draw the digraph of R (4)
(b) Give a path of length 2 from 3, if any (2)
(c) Give the domain and range of R. (4)
(d) Determine R(2)
Solution:
A= {1, 2, 3, 4, 5}
aRb ⇔(a,b) if "\\frac ab<min(a,b)"
(a) R = {(1,2),(1,3),(1,4),(1,5),(2,3),(2,4),(2,5),(3,4),(3,5),(4,5)}
Digraph of R:
(b) We need a path of length of 2 from 3. It means a = 3. When a=3, b is either 4 or 5 only from set R, i.e., (3,4), (3,5).
From (3,4), we find only one point of length 2 from above graph, which is (1,4).
From (3,5), we find only one point of length 2 from above graph, which is (1,5).
(c) For any set X = {(a,b)}, Domain is {a}, Range is {b}.
So, domain of R = {1,2,3,4}, Range of R = {2,3,4,5} from part (a).
(d) R = {(1,2),(1,3),(1,4),(1,5),(2,3),(2,4),(2,5),(3,4),(3,5),(4,5)}
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