1 Let a relation R be represented by the following matrix MR =
1000001 1111000 1 0 1 1 0 1 0
MR=1 0 0 1 0 0 0
1 1 0 1 0 0 0 0 1 0 1 1 0 1 0111100
Determine whether R is
(a) reflexive
(b) irreflexive
(c) symmetric
(d) asymmetric
(e) antisymmetric
(f) transitive
GIVE REASONS for your answer.
2 Consider the following relation R on A where A = {1, 2, 3, 4,5}
aRb ⇔ ab < min(a, b)
For example, 2R4 since 24 = 12 and min(2,4) = 2 and 12 < 2.
(a) Draw the digraph of R
(b) Give a path of length 2 from 3, if any
(c) Give the domain and range of R.
(d) Determine R
1.The matrix can be written in relation form,
a) To be reflexive relation should satisfy
(a,a) for all elements i.e all diagonal elemtents must be 1
hence the relation is Not Reflexive.
b)It is Not Irreflexive .
To be irreflexive all diagonal elements must be 0
But (1,1) is present.
c) To be symmetric it should satisfy
if(a, b) is present then (b,a) must me present
It does not satisfy for (1,7) because (7,1) is not present hence the relation is not symmetric.
d) To be asymmetric
if(a, b) is present then (b, a) should not be present.
but (1,1) is present therefore Not Asymmetric.
e) To be antisymmetric
if(a,b) and (b,a) is present then a must be equal to b
hence the relation satisfy and it is Antisymmetric.
f)To be in transitive it should satisfy
if (a,b ) and ( b,c) is present then (a,c) must be present.
But here for no element this property is satisfied hence it is Not Transitive.
2.For A={1,2,3,4,5}
The Relation R is given as-
R={(1,2),(1,3),(1,4),(1,5),(2,2),(2,3),(2,4),(2,%),(3,2),(3,3),(3,4),(3,5),(4,3),(4,4),(4,5),(5,3),(5,4),(5,5)}
(a) Diagraph is-
(b)These are paths of length 2 from vertex 3.
"P_1:3\\to 2 \\to 5\n\\\\\nP_2:3\\to 2 \\to 4\n\\\\\nP_3:3\\to 2 \\to 3\\\\\n\nP_4:3\\to 4 \\to 5\\\\\n\\\\"
(c) Domain (R)={1,2,3,4,5}
Range (R)={2,3,4,5}
By definition
Domain (R)={"x\\in A:(x,y)\\in R" }
Range (R)={"y\\in A:(x,y)\\in R" }
(d) R={"(a,b)\\in A\\times A:\\dfrac{a}{b}<min(a,b)" }
{(1,2),(1,3),(1,4),(1,5),(2,2),(2,3),(2,4),(2,%),(3,2),(3,3),(3,4),(3,5),(4,3),(4,4),(4,5),(5,3),(5,4),(5,5)}
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