Answer to Question #191575 in Discrete Mathematics for Leia

Question #191575

(a) How many code words over a, b, c, d of length 20 contain exactly 10 a’s?

(b) How many contain exactly 10 a’s and 5b’s.


1
Expert's answer
2021-05-18T13:54:10-0400

(a) Remaining 20-10=10 places to be filled with b,c,d. Each of these places can be filled in 3 ways. Hence total number of ways of filling is 310.3^{10}. Out of 20 places 10 places can be chosen in (2010)(\begin{matrix} 20\\ 10 \end{matrix}) ways. Hence answer is 3103^{10}(2010)(\begin{matrix} 20\\ 10 \end{matrix}) .

(b) Here as before we need to fill 5 places with c and d. This can be done in 252^5 ways. The 5 places can be chosen in (205)(\begin{matrix} 20\\ 5 \end{matrix}) ways. Now a and b with first one 10 times repeated and b 5 times repeated can be done in 15!10!5!\frac{15!}{10!5!} ways. Hence no of words is 25(205)2^5 (\begin{matrix} 20\\ 5 \end{matrix}) 15!10!5!\frac{15!}{10!5!} ways.


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