(a) How many code words over a, b, c, d of length 20 contain exactly 10 a’s?
(b) How many contain exactly 10 a’s and 5b’s.
(a) Remaining 20-10=10 places to be filled with b,c,d. Each of these places can be filled in 3 ways. Hence total number of ways of filling is "3^{10}." Out of 20 places 10 places can be chosen in "(\\begin{matrix}\n20\\\\\n10\n\\end{matrix})" ways. Hence answer is "3^{10}""(\\begin{matrix}\n20\\\\\n10\n\\end{matrix})" .
(b) Here as before we need to fill 5 places with c and d. This can be done in "2^5" ways. The 5 places can be chosen in "(\\begin{matrix}\n20\\\\\n5\n\\end{matrix})" ways. Now a and b with first one 10 times repeated and b 5 times repeated can be done in "\\frac{15!}{10!5!}" ways. Hence no of words is "2^5 (\\begin{matrix}\n20\\\\\n5\n\\end{matrix})" "\\frac{15!}{10!5!}" ways.
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