Question #191100

A = Q, (a*b) = a + b


1
Expert's answer
2021-05-10T13:03:34-0400

A=Q(ab)=a+bA=Q\left(a\cdot b\right)=a+b


In the above expression, the identity element of the binary operation is zero.

From the identity's explanation e is the identity element if; ae=a=eaa\cdot e=a=e\cdot a


The binary operation in our case will be: ab=a+baba\cdot b=a+b-ab

Letting e to be the binary element we get :

ae=aa\cdot e=a\:\:

a+eae=aa+e-ae=a

By subtracting a from both sides we get:

eae=0e-ae=0\:

e(1a)=0e\left(1-a\right)=0


a=1ande=0a=1\:and\:e=0


Therefore, the value of a can not be equal 1 because the binary operation * defined on Q-( 1 ).



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