Answer to Question #157851 in Discrete Mathematics for Kai

Question #157851

Inclusion-Exclusion Principle


A group of 191 students, which are taking French, business and music; 36 are taking French and business; 20 are taking French and music; 18 are taking business and music; 65 are taking French, 76 are taking business and 63 are taking music. 


-How many are taking French and music but not business?

- How many are taking business and neither French nor music?

- How many are taking French or business (Or both?)

-How many are taking music or french (or both) but not business?

- How many are taking none of the three subjects?


1
Expert's answer
2021-01-31T17:48:09-0500

Let

A is set of students who are taking French

B is set of students who are taking business

C is set of students who are taking music

U is set of all students

Then we have:

U=191,A=65,B=76,C=63|U|=191, |A|=65, |B|=76, |C|=63

AB=36,AC=20,BC=18|A|\bigcap B|=36, |A|\bigcap C|=20, |B|\bigcap C|=18

U=A+B+CABACBC+ABC|U|=|A|+|B|+|C|-|A\bigcap B|-|A\bigcap C|-|B\bigcap C|+|A\bigcap B\bigcap C|

ABC=191657663+36+20+18=61|A\bigcap B\bigcap C|=191-65-76-63+36+20+18=61

But ABC18|A\bigcap B\bigcap C|\leq18

So, let ABC=10|A\bigcap B\bigcap C|=10

Then:


Who are taking French and music but not business:

ACABC=2010=10|A\bigcap C|-|A\bigcap B \bigcap C|=20-10=10

Who are taking business and neither French nor music:

BBCAB+ABC=761836+10=22|B|-|B|\bigcap C|-|A|\bigcap B|+|A\bigcap B \bigcap C|=76-18-36+10=22

Who are taking French or business (or both):

A+BAB=95+7636=135|A|+|B|-|A|\bigcap B|=95+76-36=135

Who are taking music or french (or both) but not business:

A+CABBC+ABC=65+633618+10=84|A|+|C|-|A|\bigcap B|-|B|\bigcap C|+|A\bigcap B \bigcap C|=65+63-36-18+10=84

Who are taking none of the three subjects:

U(A+B+CABACBC+ABC)=|U|-(|A|+|B|+|C|-|A\bigcap B|-|A\bigcap C|-|B\bigcap C|+|A\bigcap B\bigcap C|)=

=191657663+36+20+1810=51=191-65-76-63+36+20+18-10=51


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