Find the negation of each: 1.
∃
x ( (x+3=2) ^ (x
-
2 =1))
∄x((x+3=2)∧(x−2=1))=∀x(¬(x+3=2)∨¬(x−2=1))=∀x((x+3≠2)∨(x−2≠1))=∀x(x≠−1∨x≠3)\nexists x ( (x+3=2) \land (x-2 =1)) = \forall x (\lnot(x+3=2) \lor \lnot (x-2 =1)) = \forall x ((x+3\ne2) \lor (x-2 \ne 1)) = \forall x (x\ne -1\lor x\ne 3)∄x((x+3=2)∧(x−2=1))=∀x(¬(x+3=2)∨¬(x−2=1))=∀x((x+3=2)∨(x−2=1))=∀x(x=−1∨x=3)
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