Question #146302

Show that the relation R=∅ on a nonempty set S is symmetric and transitive, but not reflexive.

Expert's answer

A binary relation RR is called reflexive if (a,a)∈R(a,a)\in R for any a∈S.a\in S. Since SS is a nonempty set, there is an element s∈S.s\in S. Taking into account that R=∅R=\emptyset, we conclude that (s,s)∉R(s,s)\notin R and thus RR is not reflexive.


A binary relation RR on a set SS is called symmetric if (a,b)∈R(a,b)\in R implies (b,a)∈R(b,a)\in R. Since R=∅R=\emptyset, the statement "(a,b)∈R(a,b)\in R" is false. Therefore, the implication "if (a,b)∈R(a,b)\in R then (b,a)∈R(b,a)\in R" is true. So, the relation R=∅R=\emptyset is symmetric.


A binary relation RR on a set SS is called transitive if (a,b)∈R(a,b)\in R and (b,c)∈R(b,c)\in R implies (a,c)∈R(a,c)\in R. Since R=∅R=\emptyset, the statement "(a,b)∈R(a,b)\in R and (b,c)∈R(b,c)\in R" is false. Therefore, the implication "if (a,b)∈R(a,b)\in R and (b,c)∈R(b,c)\in R then (a,c)∈R(a,c)\in R" is true. So, the relation R=∅R=\emptyset is transitive.



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