Question #136808

Compute the values of the sums below.
(a)5∑(k=1) (k+ 1)
(b)4∑(j=0) (-2) ^j
(c) 10∑(i=1) 3
(d) 8∑(j=0) ( 2^(j+1) -2^j )

Expert's answer

(a) 5k=1+(k+1)=5limn+k=1n(k+1)=5limn+(n+2)(n+1)2=+5\sum_{k=1}^{+\infty}(k+1)=5\, lim_{n\rightarrow+\infty}\sum_{k=1}^{n}(k+1)=5\, lim_{n\rightarrow+\infty}\frac{(n+2)(n+1)}{2}=+\infty

(b) 4j=0+(2)j=4limn+j=0n(2)j=limn+(2)n+113=4\sum_{j=0}^{+\infty}(-2)^j=4\, lim_{n\rightarrow+\infty}\sum_{j=0}^{n}(-2)^j\, =lim_{n\rightarrow+\infty}\frac{(-2)^{n+1}-1}{-3}=\infty

(c) 10i=1+3=+10\sum_{i=1}^{+\infty}3=+\infty

(d) 8j=0+(2j+12j)=8limn+j=0n(2j+12j)=8\sum_{j=0}^{+\infty}(2^{j+1}-2^{j})=8\,\,lim_{n\rightarrow+\infty}\sum_{j=0}^{n}(2^{j+1}-2^{j})=

=8limn+(2n+11)=+=8\,\,lim_{n\rightarrow+\infty}(2^{n+1}-1)=+\infty


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