Define f:(0,1] →R as follows.
For n∈N, n≥2, f(1/n)=1/(n−1) and for all other x∈(0,1] , f(x)=x
Since the "equivalent to" relation is both symmetric and transitive, it should follow that (0,1] is equivalent to [0,∞)2. Hence, there does exist a one-to-one correspondence between (0,1] and [0, ∞)2
Comments
Leave a comment