1.1) Given function "f(x)=sin(x)" is one-one in the given domain and "f(-\\pi\/2) = -1, f(\\pi\/2) = 1" so given function is onto also.
Hence, given function is invertible.
Now, "f(x) = sin(x) \\implies y = sin(x) \\implies x = sin^{-1} (y)".
So, Inverse function is "g(x) = sin^{-1}(x)" , since "(fog)(x) = (gof)(x) = x" .
1.2) Given function is one-one in the given domain and "f(0) = 2, f(\\pi) = -2", hence the given function is onto also. Hence given function is onto.
Now, "y = 2cos(x) \\implies x = cos^{-1}(y\/2)".
So, Inverse function is "g(x) = cos^{-1}(x\/2)" since "(fog)(x) = (gof)(x) = x ."
2) Given "f(x) = (5\/9)(x-32) \\implies y = (5\/9)(x-32)"
"\\implies x = (\\frac{9}{5}y)+32".
Hence, Opposite function for the opposite conversion is "g(x) = \\frac{9}{5} x +32."
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