1.1) Given function f(x)=sin(x) is one-one in the given domain and f(−π/2)=−1,f(π/2)=1 so given function is onto also.
Hence, given function is invertible.
Now, f(x)=sin(x)⟹y=sin(x)⟹x=sin−1(y).
So, Inverse function is g(x)=sin−1(x) , since (fog)(x)=(gof)(x)=x .
1.2) Given function is one-one in the given domain and f(0)=2,f(π)=−2, hence the given function is onto also. Hence given function is onto.
Now, y=2cos(x)⟹x=cos−1(y/2).
So, Inverse function is g(x)=cos−1(x/2) since (fog)(x)=(gof)(x)=x.
2) Given f(x)=(5/9)(x−32)⟹y=(5/9)(x−32)
⟹x=(59y)+32.
Hence, Opposite function for the opposite conversion is g(x)=59x+32.
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