Determine the laplace transform for ∂u/∂t and ∂u/∂x. Hence using the laplace transform method, solve the partial differential equation ∂u/∂t=u-∂u/∂x. subject to the initial condition u(x,0)=e-7x,x>0,t>0
Apply the method of Varition of parameter
d^2y/dx^2 -4 dy/dx +3 y = 1/1+e^-x
Solve the method of undermined coefficient (D^2+8D+16)y=8e^-2x ; y(0)= 2 y'(0)= 0
what is the separable variable? dy/dx = y² sin x², y(-2) = 1/3?
y' = csc x - y cot x
(3xy+3y-4)dx+(x+1)^2dy=0
\left(x-y\right)dx+\left(3x+y\right)dy=0
Determine the solution of the following differential equation:
xxy '= 1 + y^2