Let's put X=x2;Y=y2 then p=yxdXdY . Let's denote P=dXdY
Then the equation can be rewritten in form
X(y−x2yP)=yy2x2P2
By multiplying both sides with y, we assume
X(y2−x2P)=x2P2
Or
X(Y−XP)=XP2
Therefore
Y=XP+P2
which is now in Clairaut’s form
The solution got by just replacing P by constant c.
Hence
Y=cX+c2
or
y2=cx2+c2
Comments