Question #92854
Reduce the equation x²(y-px)=yp² to clairaut´s form and hence find its complete solution.
1
Expert's answer
2019-08-19T13:35:42-0400

Let's put X=x2;Y=y2X=x^2;\quad Y=y^2 then p=xydYdXp=\frac{x}{y}\frac{dY}{dX} . Let's denote P=dYdXP=\frac{dY}{dX}

Then the equation can be rewritten in form

X(yx2Py)=yx2y2P2X(y-x^2\frac{P}{y})=y\frac{x^2}{y^2}P^2

By multiplying both sides with y, we assume

X(y2x2P)=x2P2X(y^2-x^2P)=x^2P^2

Or

X(YXP)=XP2X(Y-XP)=XP^2

Therefore

Y=XP+P2Y=XP+P^2

which is now in Clairaut’s form

The solution got by just replacing P by constant c.

Hence

Y=cX+c2Y=cX+c^2

or

y2=cx2+c2y^2=cx^2+c^2


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