Eliminate π, π and π from z=a(x+y)+b(xβy)+abt+c.
Differentiate the given equation partially with respect to x,y, and t
βxβzβ=a+b,βyβzβ=aβb,βtβzβ=ab
(a+b)2β(aβb)2=a2+2ab+b2βa2+2abβb2=4ab Then
(βxβzβ)2β(βyβzβ)2=4βtβzβ This is a partial differential equation of order one and degree two.
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