Find general solution of the differential equation
dy/dx=y2(1+ex)
Let us find general solution of the differential equation "\\frac{dy}{dx}=y^2(1+e^x)."
It is easy to see that "y=0" is a solution of this differential equation.
Assume that "y\\ne 0". Then "\\frac{dy}{y^2}=(1+e^x)dx".
It follows that "\\int\\frac{dy}{y^2}=\\int(1+e^x)dx". Therefore, "-\\frac{1}{y}=x+e^x+C."
We conclude that the solution is "y=0,\\ \\ -\\frac{1}{y}=x+e^x+C."
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