Answer to Question #201191 in Differential Equations for Popol

Question #201191

Find general solution of the differential equation


dy/dx=y2(1+ex)


1
Expert's answer
2021-06-01T04:39:23-0400

Let us find general solution of the differential equation dydx=y2(1+ex).\frac{dy}{dx}=y^2(1+e^x).


It is easy to see that y=0y=0 is a solution of this differential equation.


Assume that y0y\ne 0. Then dyy2=(1+ex)dx\frac{dy}{y^2}=(1+e^x)dx.


It follows that dyy2=(1+ex)dx\int\frac{dy}{y^2}=\int(1+e^x)dx. Therefore, 1y=x+ex+C.-\frac{1}{y}=x+e^x+C.


We conclude that the solution is y=0,  1y=x+ex+C.y=0,\ \ -\frac{1}{y}=x+e^x+C.



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