Question #195591

X3+x2y-xy2+y3/x2y+xy2

whetther homogeneous or not by dx/dy



1
Expert's answer
2021-05-20T13:57:07-0400

Ans:-

F(x,y)=x3+x2yxy2+y3x2y+xy2F(x,y)=\dfrac{x^3+x^2y-xy^2+{y^3}}{{x^2y}+xy^2}\\


For finding equation homogeneous or not

Put x=λxx=\lambda x and y=λyy=\lambda y


F(λx,λy)=λ3x3+λ3x2yλ3xy2+λ3y3λ3x2y+λ3xy2F(\lambda x,\lambda y)=\dfrac{\lambda^3 x^3+\lambda^3 x^2 y-\lambda^3 xy^2+\lambda^3 y^3}{\lambda^3 x^2y+\lambda^3 xy^2}


F(λx,λy)=x3+x2yxy2+y3x2y+xy2\Rightarrow F(\lambda x,\lambda y)=\dfrac{x^3+x^2y-xy^2+{y^3}}{{x^2y}+xy^2}\\


F(λx,λy)=F(x,y)\Rightarrow F(\lambda x,\lambda y)=F(x,y)


Thus F(x,y)F(x,y) is Homogeneous function of degree zero. Therefore, the given differential equation is homogeneous differential equation.


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