Question #165461

x dy/dx = y + x


1
Expert's answer
2021-02-24T05:56:29-0500

xy=y+xxy'=y+x

y=yx+1y'=\frac{y}{x}+1

Let y=zxy=zx, then yx=z\frac{y}{x}=z and y=z+zxy'=z+z'x. Then we have

z+zx=z+1z+z'x=z+1, so z=1xz'=\frac{1}{x}

z=lnx+Cz=\ln|x|+C, so we have y=zx=xlnx+Cxy=zx=x\ln|x|+Cx

Answer: y=xlnx+Cxy=x\ln|x|+Cx


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