x dy/dx = y + x
"xy'=y+x"
"y'=\\frac{y}{x}+1"
Let "y=zx", then "\\frac{y}{x}=z" and "y'=z+z'x". Then we have
"z+z'x=z+1", so "z'=\\frac{1}{x}"
"z=\\ln|x|+C", so we have "y=zx=x\\ln|x|+Cx"
Answer: "y=x\\ln|x|+Cx"
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