x dy/dx = y + x
xy′=y+xxy'=y+xxy′=y+x
y′=yx+1y'=\frac{y}{x}+1y′=xy+1
Let y=zxy=zxy=zx, then yx=z\frac{y}{x}=zxy=z and y′=z+z′xy'=z+z'xy′=z+z′x. Then we have
z+z′x=z+1z+z'x=z+1z+z′x=z+1, so z′=1xz'=\frac{1}{x}z′=x1
z=ln∣x∣+Cz=\ln|x|+Cz=ln∣x∣+C, so we have y=zx=xln∣x∣+Cxy=zx=x\ln|x|+Cxy=zx=xln∣x∣+Cx
Answer: y=xln∣x∣+Cxy=x\ln|x|+Cxy=xln∣x∣+Cx
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