By separating variables
= x³dx
=> sec y dy = x³dx
Integrating ,
sec y dy = x³dx + C
=> ln |sec y + tan y| = + C , C is integration constant
This is the general solution
In alternative form the answer can be given as below.
4ln | sec y + tan y | = x⁴ + 4C
=> ln |sec y + tan y |⁴ = x⁴+4C
=> (sec y + tan y)⁴ = e
=> (sec y + tan y)⁴ = e4C. e
=> (sec y + tan y)⁴ = A e
Where A =e4C is integration constant
The general solution of the given differential equation is
(sec y + tan y)⁴ = A e where A is integration constant
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