Question #122417
dy/dx=x^3cosy
1
Expert's answer
2020-06-15T17:41:57-0400

dydx=x3cosy\frac {dy}{dx} = x^3cosy

By separating variables

dycosy\frac {dy}{cosy} = x³dx

=> sec y dy = x³dx

Integrating ,

\int sec y dy = \int x³dx + C

=> ln |sec y + tan y| = x44\frac{x^4}{4} + C , C is integration constant

This is the general solution


In alternative form the answer can be given as below.

4ln | sec y + tan y | = x⁴ + 4C

=> ln |sec y + tan y |⁴ = x⁴+4C

=> (sec y + tan y)⁴ = ex4+4C^{x^4+4C}

=> (sec y + tan y)⁴ = e4C. ex4^{x^4}

=> (sec y + tan y)⁴ = A ex4^{x^4}

Where A =e4C is integration constant

Answer\mathbf {Answer}

The general solution of the given differential equation is

(sec y + tan y)⁴ = A ex4^{x^4} where A is integration constant



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