Question #102570
Solve the differential equation y''=1+(y')^2
1
Expert's answer
2020-02-09T16:51:39-0500

We want to solve

y=1+(y)2y''=1+(y')^2


The usual thing is to replace y=vy'=v and therefore we get

v=1+v2.v'=1+v^2.


This ODE can be solved by the usual methods, just use what you know. For example separation of variables i.e. solve for v

dv1+v2=dx\int \frac{dv}{1+v^2} = \int dx

arctan(v)=x+C.arctan(v)=x+C.


We get v(x)=tan(x+C)v(x)=\tan(x+C) where C is some constant. Now resubstitute i.e.


y=v=tan(x+C)y'=v=\tan(x+C)


Just integrate both sides with respect to x i.e.

y(x)=tan(x+C) dxy(x)=\int \tan(x+C) \ dx

This can be solved easily, for example use substitution s=cos(x+C)s=\cos(x+C)


tan(x+C) dx=dss=log(s)=log(cos(x+C))\int \tan(x+C) \ dx=-\int \frac{ds}{s}=-\log(s)=-\log(\cos(x+C))


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