(x−2)2=4
x1=0,x2=4
A=∫04(4−(x−2)2)dx=[4x−3(x−2)3]40
=16−38−(0+38)=332
xˉ=A1∫04x(4−(x−2)2)dx
=323∫04(−x3+4x2)dx=323[−4x4+34x3]40
=323(−64+3256)=2
yˉ=A1∫0421((4−(x−2)2))2dx
=643∫04(x4−8x3+16x2)dx
=643[5x5−2x4+316x3]40
=643(51024−512+31024)=58 (2,58)
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