Question #342049

Consider the equation xe^x = cos x


(a) Apply the intermediate value theorem to show that the function has a root in the interval


[0, 1].




1
Expert's answer
2022-05-18T09:10:20-0400

Function f(x)=xexcosxf(x)=xe^x-\cos x is continuous on [0,1].[0, 1].


f(0)=0(e0)cos(0)=1<0f(0)=0(e^0)-\cos(0)=-1<0

f(1)=1(e1)cos(1)=ecos(1)>0,f(1)=1(e^1)-\cos(1)=e-\cos (1)>0,

since e>1,cos(1)<1.e>1, \cos(1)<1.

Then by the intermediate value theorem there exists the number cc in (0,1)(0, 1) such that f(c)=0.f(c)=0.

Therefore the function f(x)=xexcosxf(x)=xe^x-\cos x has a root in the interval [0,1].[0, 1].



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Comments

Assignment Expert
20.05.22, 13:31

Yes, this function is also continuous.


Belay
19.05.22, 11:25

Thank you for your answer. Can we say a function f(x) = cosx - xe^x is continuous on [0, 1]? instead of the above function written f(x) = xe^x - cosx

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