Air is pumped into a spherical balloon at the rate of 100 cm3/s. How fast is the diameter increasing when the diameter is 10 cm?
V=4/3πr3V=4/3\pi r^3V=4/3πr3
r=0.5Dr=0.5 Dr=0.5D
V=4/3π(0.5D)3=1/6πD3V=4/3\pi (0.5D)^3=1/6 \pi D^3V=4/3π(0.5D)3=1/6πD3
dV/dt=1/2πD2dD/dtdV/dt=1/2\pi D^2 dD/dtdV/dt=1/2πD2dD/dt
dD/dt=(dV/dt)/(0.5πD2)=100/(0.5(10)3.14)=6.37cm/sdD/dt=(dV/dt)/(0.5\pi D^2)=100/(0.5(10)3.14)=6.37 cm/sdD/dt=(dV/dt)/(0.5πD2)=100/(0.5(10)3.14)=6.37cm/s
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