Question #331460

Use the bissection method to approximate the root of f(x)=2x^2-1 in the interval (0,1). Let ε =0.1be the margin of error of approximation.0.1be the margin of error of approximation.


1
Expert's answer
2022-04-21T11:40:58-0400

The initial interval is (0,1)(0,1) and f(0)=1,f(1)=1f(0)=-1, f(1)=1 .

Step 1: m=(0+1)/2=0.5m=(0+1)/2=0.5 and f(m)=f(0.5)=0.5.f(m)=f(0.5)=-0.5. New interval is (0.5,1)(0.5,1)

Step 2: m=(0.5+1)/2=0.75m=(0.5+1)/2=0.75 and f(m)=f(0.75)=0.125f(m)=f(0.75)=0.125 New interval is (0.5,0.75)(0.5,0.75)

Step 3: m=(0.5+0.75)/2=0.625m=(0.5+0.75)/2=0.625 and f(m)=f(0.625)=0.21875f(m)=f(0.625)=-0.21875 New interval is (0.625,0.75)(0.625,0.75)

Step 4: m=(0.625+0.75)/2=0.6875m=(0.625+0.75)/2=0.6875 and f(m)=f(0.6875)=0.0546875f(m)=f(0.6875)=-0.0546875 New interval is (0.6875,0.75)(0.6875,0.75)

Since 0.750.6875=0.0625<0.10.75-0.6875=0.0625<0.1

which is the margin of error, we can stop the approximation.

The root is in the interval (0.6875,0.75)(0.6875,0.75) .


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