Question #331332

state the statement is true or false the function f[x,y]={x^2y/x^4+y^2[x,y]=0 is not continuous at [0,0] and 0,[x,y]=0



1
Expert's answer
2022-04-22T02:49:02-0400

Since it is not clear how does the function look like, consider two cases:

  1. f(x,y)=x2yx4+y2f(x,y)=\frac{x^2y}{x^4}+y^2, f(0,0)=0f(0,0)=0. Consider the line y=xy=x. We receive f(x,x)=1x+x2f(x,x)=\frac1x+x^2. The function tends to \infty as (x,y)(x,y) approaches (0,0)(0,0) along y=x.y=x. Thus, the function is not continuous at (0,0)(0,0) and it is not possible to define it in such a way that it will be continuous at (0,0)(0,0), since it approaches \infty as xx approaches along the line y=xy=x.
  2. f(x,y)=x2yx4+y2f(x,y)=\frac{x^2y}{x^4+y^2}, f(0,0)=0.f(0,0)=0. Consider the parabola y=x2y=x^2. We receive f(x,x2)=12f(x,x^2)=\frac12. On the other hand, consider the line y=xy=x. We receive: f(x,x)=x3x4+x2f(x,x)=\frac{x^3}{x^4+x^2}. The latter approaches as xx approaches . Thus, the function is not continuous at (0,0)(0,0) and it is not possible to define it in such a way that it will be continuous, because it tends to different values along different curves as (x,y)(x,y) approaches (0,0).(0,0).

Thus, the statement is true in both cases.



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