Let u=15 cm3/sec, D=3 m, H=6 m
The volume of the cone: V=314πd2h=12πd2h,
where d - current diameter of the surface,
h - current height of the water cone.
Current water cone and the cone containing this water are the similar objects with a similarity factor of k = h / H.
d=kD=hHD⇒V=12π(HD)2h3
u=dtdV=12π(HD)2⋅3h2dtdh=π(2HDh)2dtdh⇒⇒dtdh=πu(Dh2H)2
At the point in time when the cone is almost filled h = H:
dtdh(h=H)=πu(D2)2≈3.1415(62)2≈0.53 (m/sec)
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