Question #329296

Evaluate the following


ni=1(3/2(i1))n\sum i=1 (3/2^(i-1))


1
Expert's answer
2022-04-16T05:38:05-0400

The aim is to compute the sum: ni=0nin\sum_{i=0}^ni. The sum i=0ni\sum_{i=0}^ni is an arithmetic progression. It is a well-known formula. ni=0ni=n(0+1+2++n)=n(n(n+1)2)=n2(n+1)2.n\sum_{i=0}^ni=n(0+1+2+\ldots+n)=n\left(\frac{n(n+1)}{2}\right)=\frac{n^2(n+1)}{2}.


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