Evaluate the following
"n\\sum i=1 (3\/2^(i-1))"
The aim is to compute the sum: "n\\sum_{i=0}^ni". The sum "\\sum_{i=0}^ni" is an arithmetic progression. It is a well-known formula. "n\\sum_{i=0}^ni=n(0+1+2+\\ldots+n)=n\\left(\\frac{n(n+1)}{2}\\right)=\\frac{n^2(n+1)}{2}."
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