Find the center of the mass of the four particles having the masses of 2, 3, 3 and 4 kg and located at the points (-1, -2), (1, 3), (0, 5), and (2, 1), respectively.
The coordinates "\\overrightarrow{R}" of the center of mass can be found using the formula
"\\displaystyle \\overrightarrow{R}=\\frac1M\\sum_{i=0}^{n} m_i\\overrightarrow{r_i}" , where "\\displaystyle M=\\sum_{i=0}^n m_i" is the total mass of all of the particles.
"\\displaystyle M=2+3+3+4=12" (kg)
"\\displaystyle \\overrightarrow{R}=\\frac{1}{12}(2\\cdot(-1,-2)""+3\\cdot(1,3)+3\\cdot(0,5)+4\\cdot(2,1))" "=\\frac{1}{12}(9,24)=(\\frac34,2)" .
Answer: Coordinates of the center of the mass are "(\\frac34,2)" .
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