Evaluate ā«c š¹. šš,where š¹ = š^2 ā š^2š + š„š¦š and curve š¶ is the arc of the curve š¦ = š^3 from (0,0) to (2,8).
ā«CFdr=[y=x3dy=3x2dxx:0ā2F1=x2āy2=x2āx6F2=xy=x4]=ā«02(x2āx6)dx+x4ā 3x2dx==(x33+2x77)ā£02=82421\int_C{Fdr}=\left[ \begin{array}{c} y=x^3\\ dy=3x^2dx\\ x:0\rightarrow 2\\ F_1=x^2-y^2=x^2-x^6\\ F_2=xy=x^4\\\end{array} \right] =\int_0^2{\left( x^2-x^6 \right) dx+x^4\cdot 3x^2dx}=\\=\left( \frac{x^3}{3}+\frac{2x^7}{7} \right) |_{0}^{2}=\frac{824}{21}ā«CāFdr=ā£ā”āy=x3dy=3x2dxx:0ā2F1ā=x2āy2=x2āx6F2ā=xy=x4āā¦ā¤ā=ā«02ā(x2āx6)dx+x4ā 3x2dx==(3x3ā+72x7ā)ā£02ā=21824ā
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